Let d be range d2=(h+R)2−R2 =h2+R2+2RH−R2 d2=h2+2Rh as R>≫>> h then d≈√2‌Rh...‌... (1) ‌ Now, if coverage is to be increased 3 times 3d=√2Rh′... (2) Divide 2 and 1‌
3d
d
=√‌
2Rh′
2Rh
9=‌
h′
h
9h=h′ If h=100m then tower of height 900m is required