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Test Index
JEE Mains 25 Jan 2023 Shift 2 Paper
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Section:
Physics
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© examsnet.com
Question : 20 of 90
Marks:
+1
,
-0
Every planet revolves around the sun in an elliptical orbit :
A. The force acting on a planet is inversely proportional to square of distance from sun.
B. Force acting on planet is inversely proportional to product of the masses of the planet and the sun
C. The centripetal force acting on the planet is directed away from the sun.
D. The square of time period of revolution of planet around sun is directly proportional to cube of semi-major axis of elliptical orbit.
Choose the correct answer from the options given below :
Options :
[25-Jan-2023 Shift 2]
A and D only
C
C
C
and
D
D
D
only
B and C only
A and C only
Validate
Solution:
F
=
G
m
1
m
2
r
2
\; F =\; \frac{Gm_1 m_2}{r^2}
F
=
r
2
G
m
1
m
2
⇒
F
∝
1
r
2
\; \Rightarrow F \propto \; \frac{1}{r^2}
⇒
F
∝
r
2
1
⇒
F
∝
m
1
m
2
\; \Rightarrow F \propto m_1 m_2
⇒
F
∝
m
1
m
2
⇒
This force provides centripetal force and acts
\; \Rightarrow \; \text{ This force provides centripetal force and acts } \;
⇒
This force provides centripetal force and acts
towards sun
\;\; \text{ towards sun } \;
towards sun
⇒
T
2
∝
a
3
(Kepler’s third law)
\; \Rightarrow T^2 \propto a^3 \; \text{ (Kepler's third law) } \;
⇒
T
2
∝
a
3
(Kepler’s third law)
© examsnet.com
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