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JEE Mains 25 Jan 2023 Shift 1 Paper
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Section:
Chemistry
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Question : 51 of 90
Marks:
+1
,
-0
An athlete is given
100
g
100\ \mathrm{g}
100
g
of glucose
(
C
6
H
12
O
6
)
(\mathrm{C_6H_{12}O_6})
(
C
6
H
12
O
6
)
for energy. This is equivalent to
1800
k
J
1800\ \mathrm{kJ}
1800
kJ
of energy. The
50
%
50\%
50%
of this energy gained is utilized by the athlete for sports activities at the event. In order to avoid storage of energy, the weight of extra water he would need to perspire is _______
g
\mathrm{g}
g
(Nearest integer)
Assume that there is no other way of consuming stored energy.
Given : The enthalpy of evaporation of water is 45
k
J
m
o
l
−
1
\mathrm{kJ}\ \mathrm{mol}^{-1}
kJ
mol
−
1
Molar mass of
C
,
H
&
O
\mathrm{C},\ \mathrm{H}\ \&\ \mathrm{O}
C
,
H
&
O
are
12
12
12
,
1
1
1
and
16
g
m
o
l
−
1
16\ \mathrm{g}\ \mathrm{mol}^{-1}
16
g
mol
−
1
.
[25-Jan-2023 Shift 1]
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