‌1→2⇒‌ Isobaric process ‌ ‌2→3⇒‌ Isochoric process ‌ ‌3→1⇒‌ Isothermal process ‌ ‌W=W1→2+W2→3+W3→1 ‌=(−P(V2−V1)+0[−P1V1‌ln(‌
V2
V1
)]) ‌=[−1×(40−20)+0+[−1×20‌ln(‌
20
40
)]] ‌=−20+20‌ln‌2 ‌=−20+20×2.3×0.3 ‌=−6.2‌ bar ‌L ‌|W|=6.2‌ bar ‌1=620J