The potential differenced across 5µC capacitor, is V=
Q
C
=(
1000
5
)V=200V The 10Ω resistor and capacitor are in parallel arrangement and therefore current I through resistor is given by I=
V
R
=
200
10
=20A From KCL at junction A we get I=25A
Now we apply KVL in the loop ABDA, −10×20−5R2+50×5=0 ⇒R2=10Ω Apply KVL in loop ADCEFA, we get −50×5−5×10+310−25R1=0 ⇒R1=0.4Ω Apply KVL in loop ABCDA, −20×10−15R3+10×5+50×5=0 ⇒R3=6.66Ω
