Horizontal and vertical components of initial velocity are: ux = 20√2cos45° = 20 m/s and uy = 20√2sin45° = 20 m/s After 1 s horizontal component remains unchanged while the vertical component becomes vy = uy−gt = 20 - (10) (1) = 10 m/s Due to explosion one part comes to rest. Hence, from conservation of linear momentum vertical component of second part will become vy′ = 20 m/s. Therefore, maximum height attained by the second part will be H = h1+h2 Here, h1 = height attained in 1 s = (20) (1) -