=λ ‌x=3λ−3,y=λ−2,z=1−2λ P(3λ−3,λ−2,1−2λ) will satisfy the equation of plane x+y+z=2. 3λ−3+λ−2+1−2λ=2 2λ−4=2 λ=3 P(6,1,−5) Perpendicular distance of P from plane 3x−4y+12z−32=0 is ‌q=|‌
3(6)−4(1)+12(−5)−32
√9+16+144
| ‌q=6 ‌2q=12 Sum of roots =6+12=18 Product of roots =6(12)=72 ∴ Quadratic equation having q and 2q as roots is x2−18x+72.