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Test Index
Electrostatics Part 1
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Section:
Physics
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© examsnet.com
Question : 28 of 100
Marks:
+1
,
-0
In finding the electric field using Gauss Law the formula
∣
E
→
∣
=
q
e
n
e
ε
0
∣
A
∣
\left|\overset{\rightarrow}{E}\right| = \frac{q_ene}{\varepsilon_0 |A|}
E
→
=
ε
0
∣
A
∣
q
e
n
e
is applicable. In the formula
s
0
s_0
s
0
is permittivity of free space, A is the area of Gaussian surface and
q
enc
q_{\text{enc}}
q
enc
is charge enclosed by the Gaussian surface. The equation can be used in which of the following situation?
[8 Jan 2020 Shift 1]
Only when the Gaussian surface is an equipotential surface.
Only when
∣
E
→
∣
\left|\overset{\rightarrow}{E}\right|
E
→
= constant on the surface.
For any choice o f Gaussian surface.
Only when the Gaussian surface is an equipotential surface and
∣
E
→
∣
\left|\overset{\rightarrow}{E}\right|
E
→
is constant on the surface.
Validate
Solution:
∣
E
→
∣
\left|\overset{\rightarrow}{E}\right|
E
→
should be constant on the surface and the surface should be equipotential.
© examsnet.com
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