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JEE Main Physics Class 12 Electromagnetic Induction Questions
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Section:
Physics
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Question : 2
Total: 113
Two coils have mutual inductance
0.002
H
. The current changes in the first coil according to the relation
i
=
i
0
s
i
n
ω
t
, where
i
0
=
5
A
and
ω
=
50
π
rad
∕
s
. The maximum value of emf in the second coil is
π
α
V
. The value of
α
is____
[27-Jan-2024 Shift 1]
Your Answer:
Validate
Solution:
👈: Video Solution
ϕ
=
Mi
=
Mi
0
s
i
n
ω
t
EMF
=
−
M
di
dt
=
−
0.002
(
i
0
ω
cos
ω
t
)
EMF
max
=
i
0
ω
(
0.002
)
=
(
5
)
(
50
π
)
(
0.002
)
EMF
max
=
π
2
V
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