Test Index

Work, Power and Energy Part 1

Section: Physics

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Question : 68 of 100

Marks: +1, -0

An object is dropped from a height h from the ground. Everytime it hits the ground it loses 50% of its kinetic energy. The total distance covered as

t\to\infty

[Main 8 April 2017]

2h
$\infty$
$\frac{5}{3}$ h
$\frac{8}{3}$ h
None of the above

Solution:

\frac{1}{2} m v'^2 = \frac{1}{2} \frac{1}{2} m v^2

v' = \frac{v}{\sqrt{2}}

v = e u

e = \frac{1}{\sqrt{2}}

H = \lambda \left( \frac{1+e^2}{1-e^2} \right)

= h \left( \frac{1+\frac{1}{2}}{1+\frac{1}{2}} \right) = 3h

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