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Thermodynamics Part 5

Section: Physics

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Question : 85 of 86

Marks: +1, -0

A gun fires a lead bullet of temperature 300 K into a wooden block. The bullet having melting temperature of 600 K penetrates into the block and melts down. If the total heat required for the process is 625 J , then the mass of the bullet is

\;\;\;\;

grams. (Latent heat of fusion of lead

=2.5 \times 10^{4} \mathrm{JKg}^{-1}

and specific heat capacity of lead

125 \mathrm{JKg}^{-1} \mathrm{K}^{-1}

[23 Jan 2025 Shift 1]

20
5
10
15

Solution:

\;Q = m s \Delta T + m L

\;625 = m \times 125 \times 300 + m \times 2.5 \times 10^{4}

\;625 = m\{3.75+2.5\} \times 10^{4}

\;\Rightarrow \;\frac{625}{6.25} \times 10^{-4} \mathrm{kg} = 10 \mathrm{g} = m

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