First, we determine the total number of moles (ntotal)in the mixture using the Ideal Gas Law: PV = nRT. Given the values: Pressure (P): 100kPa=105Pa Volume (V): 8310cm3=8.31×10−3m3 Temperature (T): 300 K Gas Constant (R): 8.31J∕mol⋅K
PV
RT
=
105×8.31×10−3
8.31×300
=
100
300
≈0.333mole 1. Mole equation: n1+n2=0.333 2. Mass equation: 44n1+32n2=13.2 (where 44 and 32 are the molar masses of CO2 and O2 respectively) 3. Solve for individual moles Using the first equation to express n2 as 0.333–n1, we substitute this into the mass equation: 44n1+32(0.333−n1)=13.2 44n1+10.667−32n1=13.2 12n1=2.533 n1≈0.211mol Then, calculate n2: n2=0.333−0.211=0.122mol