The trajectory of a projectile in a vertical plane is y=α x-β x², where α and β are constants and x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection θ and the maximum height attained H are respectively given by [26 Feb 2021 Shift 2]

Question

Examsnet · Accepted Answer

Correct Answer is : tan⁡−1α,α24β^{-1}α, {α²}{4β}tan−1α,4βα2​

Motion in a Plane