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Motion in a Plane
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Section:
Physics
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© examsnet.com
Question : 41
Total: 85
Two projectiles
P
1
and
P
2
thrown with speed in the ratio
√
3
:
√
2
, attain the same height during their motion. If
P
2
is thrown at an angle of
60
∘
with the horizontal, the angle of projection of
P
1
with horizontal will be :
[30-Jun-2022-Shift-1]
15
∘
30
∘
45
∘
60
∘
Validate
Solution:
We know,
Maximum height of a projectile
(
H
)
=
‌
u
2
s
i
n
‌
2
θ
2
g
Given, Ratio of initial velocity of two projectile
‌
u
1
u
2
=
‌
√
3
√
2
Both projectile reach the same maximum height.
∴
H
1
=
H
2
⇒
‌
u
1
2
s
i
n
‌
2
θ
1
2
g
=
‌
u
2
2
s
i
n
‌
2
θ
2
2
g
⇒
u
1
2
s
i
n
‌
2
θ
1
=
u
2
2
s
i
n
‌
2
θ
2
⇒
(
‌
u
1
u
2
)
2
=
(
‌
s
i
n
‌
θ
2
s
i
n
‌
θ
1
)
2
⇒
(
‌
√
3
√
2
)
2
=
(
‌
s
i
n
‌
60
∘
s
i
n
‌
θ
1
)
2
⇒
‌
3
2
=
‌
3
4
s
i
n
‌
2
θ
1
⇒
s
i
n
‌
θ
1
2
=
‌
1
2
⇒
s
i
n
‌
θ
1
=
‌
1
√
2
=
s
i
n
‌
45
∘
⇒
θ
1
=
45
∘
© examsnet.com
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