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Laws of Motion Part 2

Section: Physics

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Question : 18 of 52

Marks: +1, -0

A body of mass 1 kg is suspended with the help of two strings making angles as shown in figure. Magnitudes of tensions

T_1

T_2

, respectively, are (in N )

(Take acceleration due to gravity

10\ \mathrm{m}/\mathrm{s}^2

[2 Apr 2025 Shift 2]

$5 \sqrt{3}, 5$
$5 \sqrt{3}, 5 \sqrt{3}$
$5, 5 \sqrt{3}$
5,5

Solution:

T_1 \sin 60 + T_2 \sin 30 = m g

T_1 \cos 60 = T_2 \cos 30

T_1 = \sqrt{3} T_2

\sqrt{3} T_2 \times \frac{\sqrt{3}}{2} - \frac{T_2}{2} = m g

T_2 = \frac{m g}{2} = 5\ \mathrm{N}

T_1 = \frac{\sqrt{3} m g}{2} = 5 \sqrt{3}\ \mathrm{N}

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