JEE Main Physics Class 11 Work, Energy and Power Part 1 Questions

Time taken for the particles to collide,
t=

d

Vrel

=

100

100

=1sec
Speed of wood just before collision = gt = 10 m/s and speed of bullet just before collision = v – gt
=100−10=90 m/s
S=100×1−

1

2

×10×1=95m
Now, using conservation of linear momentum just before and after the collision
– (0.03) (10) + (0.02) (90) = (0.05)v
⇒ 150=5v∴v=30m/s
Max. height reached by body
h=

30×30

2×10

=45m ∴ Height above tower = 40 m