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JEE Main Physics Class 11 Oscillations Part 2 Questions

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Question : 22

Total: 76

At a given point of time the value of displacement of a simple harmonic oscillator is given as y=A‌cos(30∘). If amplitude is 40‌cm and kinetic energy at that time is 200J, the value of force constant is 1.0×10xNm−1. The value of x is _______

[13-Apr-2023 shift 1]

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