JEE Main Physics Class 11 Laws Of Motion Part 1 Questions

Let's draw the free body diagram of the solid cylinder. Using the condition of the equilibrium of the cylinder;
In the direction of inclined plane,
T+f−mg‌sin‌60∘=0
In the perpendicular direction of inclined plane,In the perpendicular direction of inclined plane,
N−mg‌cos‌60∘=0
⇒‌‌N=mg‌cos‌60∘
The frictional force between the rough surface and cylinder is
f=µsN
⇒‌‌f=0.4mg‌cos‌60∘⇒f=0.2mg
or f=‌

mg

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