)| (64)(3)‌=16α2+64+16α2‌ (given, area ‌=8√3) ‌‌=|(
∧
i
+α
∧
j
+3
∧
k
)×(3
∧
i
−α
∧
j
+
∧
k
)| (64)(3)‌‌=16α2+64+16α2‌ (given, area ‌=8√3‌ ) ‌ ‌‌ (squaring on both sides) ‌ ⇒‌‌α2=4 Now, a. b =3−α2+3 =6−α2=6−4=2