f"(2) ......(ii) f"(x)=6x−6......... (iii) Now is 3rd equation f"(2)=12−6=6 f"(11=0) Use (ii) f′(x)=3x2−6x−
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f"(2) f′(x)=3x2−6x−
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×6 f′(x)=3x2−6x−9 f′(x)=0 3x2−6x−9=0 ⇒x=−1&3 Use (iii) f"(x)=6x−6 f"(−1)=−12<0 maxima f"(3)=12>0 minima. Use (i) f(x)=x3−3x2−