0 For minimum value of sum of area f'(x) = 0 x=2/{\pi+4}\Rightarrowr=1/{\pi+4} \Rightarrowx=2r" >

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Application of Derivatives Part 1

Section: Mathematics

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Question : 63

Total: 100

A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then:

(4−π)x=πr
x=2r
2x=r
2x=(π+4)r

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