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Test Index
JEE Main Math Class 12 Three Dimensional Geometry Part 3 Questions
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Section:
Mathematics
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© examsnet.com
Question : 2
Total: 114
The distance, of the point
(
7
,
−
2
,
11
)
from the line
x
−
6
1
=
y
−
4
0
=
z
−
8
3
along the line
x
−
5
2
=
y
−
1
−
3
=
z
−
5
6
, is :
[27-Jan-2024 Shift 1]
12
14
18
21
Validate
Solution:
👈: Video Solution
B
=
(
2
λ
+
7
,
−
3
λ
−
2
,
6
λ
+
11
)
Point B lies on
x
−
6
1
=
y
−
4
0
=
z
−
8
3
2
λ
+
7
−
6
1
=
−
3
λ
−
2
−
4
0
=
6
λ
+
11
−
8
3
−
3
λ
−
6
=
0
λ
=
−
2
B
⇒
(
3
,
4
,
−
1
)
AB
=
√
(
7
−
3
)
2
+
(
4
+
2
)
2
+
(
11
+
1
)
2
=
√
16
+
36
+
144
=
√
196
=
14
© examsnet.com
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