y=x2+px−3 is a parabola at x=0⇒y=−3 Parabola cuts the y-axis at (0,−3) Equation of circle will be (x+1)2+(y+1)2=(0+1)2+(−3+1)2 ⇒(x+1)2+(y+1)2=5 ⇒x2+y2+2x+2y−3=0 Now this circle cuts x-axis at y=0 x2+2x−3=0 ⇒(x+3)(x−1)=0 ⇒x=−3,1 (−3,0) and (1,0) Points P,Q and R are (0,−3)(−3,0) and (1,0) Area of (△PQR)=