Let H:a2x2−b2y2=1(b2=a2(e2−1))∴eqn of C1=x2+y2=a2Ar.=36ππa2=36πa=6Now radius of C2 can be a(e−1) or a(e +1) for r=a(e−1) for r=a(e+1)Ar. =4ππr2=4ππa2(e−1)2=4πa2(e+1)2=436π(e−1)2=4π36(e+1)2=4e−1=31e+1=31e=34−32Not possible∴b2=36(916−1)=28∴LR=a2b2=62×28=328