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Functions Part 2
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Section:
Mathematics
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© examsnet.com
Question : 13
Total: 56
Let
f
(
x
)
=
‌
2
x
+
2
+
16
2
2
x
+
1
+
2
x
+
4
+
32
. Then the value of
8
(
f
(
‌
1
15
)
+
f
(
‌
2
15
)
+
.
.
.
+
f
(
‌
59
15
)
)
is equal to
[24 Jan 2025 Shift 1]
118
92
102
108
Validate
Solution:
👈: Video Solution
‌
f
(
x
)
=
‌
2
x
+
2
+
16
2
2
x
+
1
+
2
x
+
4
+
32
=
‌
4
(
2
x
+
4
)
2
(
2
2
x
)
+
16
(
2
x
)
+
32
‌
=
‌
2
(
2
x
+
4
)
(
2
x
+
4
)
2
=
‌
2
2
x
+
4
Now,
f
(
x
)
+
f
(
4
−
x
)
=
‌
2
2
x
+
4
+
‌
2
2
4
−
x
+
4
‌
=
‌
2
2
x
+
4
+
‌
2
×
2
x
16
+
4
×
2
x
=
‌
2
2
x
+
4
+
‌
2
x
2
(
4
+
2
x
)
‌
=
‌
1
2
So,
f
(
‌
1
15
)
+
f
(
‌
59
15
)
=
‌
1
2
‌
f
(
‌
2
15
)
+
f
(
‌
58
15
)
=
‌
1
2
‌
‌
and
‌
f
(
‌
30
15
)
=
‌
2
4
+
4
=
‌
1
2
‌
∴
8
(
f
(
‌
1
15
)
+
f
(
‌
2
15
)
+
.
.
.
f
(
‌
59
15
)
)
‌
=
8
(
‌
29
2
+
‌
1
4
)
=
118
© examsnet.com
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