(1−x)r∕10 If this term is independent of ' t′, then we havel 0−2r=0 gives, r=5 ∴‌‌T6=‌10C5(x)1(1−x)1∕2 ∴‌‌T6=‌10C5(x)1(1−x)1∕2 Let f(x)=x(1−x)1∕2, to obtain its maximum value, we have to differentiate it and equate it to 0 . i.e. f′(x)=0⇒‌