Meq of H2SO4 used by NH3=12.5×1×2=25 % of N in the compound =‌
25×10−3×14×100
0.55
=63.6 Meq. of H2SO4= Meq. of NH3 12.5×1×2=25 meq. of NH3 =25 millimoles of NH3 So Millimoles of ' N′=25 Moles of ' N′=25×10−3 wt. of N=14×25×10−3 %N=‌