6.93×10−3=k×(0.1)x(0.2)y‌. ‌ 6.93×10−3=k×(0.1)x(0.25)y From the above equation, y=0 and 1.386×10−2=k×(0.2)x(0.30)y Divide equation (i) by (iii), we get ‌
1
2
=(‌
1
2
)x⇒x=1 So r=k×(0.1)×(0.2)0 6.93×10−3=k×0.1×(0.2)0 k=6.93×10−2 t1∕2=‌