It has two 3-centre-2-electron bonds and four 2-centre-2-electron bonds. Hence, all B−H bonds are not equivalent. It is an electron deficient compound as the octet of boron is incomplete. Hence, it can behave as a Lewis acid. It can be synthesized from both BF3 and NaBH4 2BF3+6‌NaH‌
450K
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‌B2‌H6+6‌NaF 2NaBH4+I2→B2H6+2‌NaI+H2 It is a non-planar molecule. Hence, only Statements (C) and (D) are correct.