Test Index

Hydrocarbons Part 1

Section: Chemistry

Question : 31 of 100

Marks: +1, -0

${CH}_{3} {COCl} \/ {AlCl}_{3}, {Br}_{2} \/ {AlBr}_{3}, {HNO}_{3} \/ {H}_{2} {SO}_{4}$ , ${Zn} \/ {HCl}$
${CH}_{3} {COCl} \/ {AlCl}_{3}, {Zn}- {Hg} \/ {HCl}, {Br}_{2} \/ {AlBr}_{3}$ , ${HNO}_{3} \/ {H}_{2} {SO}_{4}$
${Br}_{2} \/ {AlBr}_{3}, {CH}_{3} {COCl} \/ {AlCl}_{3}, {HNO}_{3} \/ {H}_{2} {SO}_{4}$ , ${Zn} \/ {HCl}$
${HNO}_{3} \/ {H}_{2} {SO}_{4}, {Br}_{2} \/ {AlCl}_{3}, {CH}_{3} {COCl} \/ {AlCl}_{3}$ , ${Zn}- {Hg} \/ {HCl}$

Solution:

Benzene on reaction with

{CH}_{3} {COCl} \/ {AlCl}_{3}

gives acetophenone which on reduction with

{Zn}- {Hg} \/ {HCl}

gives ethyl benzene.
Bromination of ethyl benzene give 4-bromo-ethylbenzene which upon nitration gives 4-bromo-2-nitroethyl benzene.

[-l-effect of Br directs

{NO}_{2}^{-}

at its meta-position]
So, option (b) is the correct sequence of reagents used.

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