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Chemical Equilibrium Part 1

Section: Chemistry

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Question : 6 of 100

Marks: +1, -0

At

-20^{∘} {\C}

1 {\atm}

pressure, a cylinder is filled with equal number of

{\H}_2 . {\I}_2

{\HI}

molecules for the reaction

{\H}_2( {\g})+ {\I}_2( {\g}) ⇌ 2 {\HI}( {\g}), ∣

{\K}_{ {\P}}

for the process is

{\x} × 10^{-1} ⋅ {\x}=

[6 Apr 2024 Shift 1]

2
1
10
0.01

Solution:

∆ {\n}_{ {\g}}=0\; {\K}_{ {\p}}=\;{ ( {\n}_{ {\HI}}) ^2}/{ {\n}_{ {\H}_2} {\n}_{ {\I}_2}} (\;{ {\P}_{ {\T}}}/{ {\n}_{ {\T}}}) ^{∆ {\n}_{ {\g}}}

{\n}_{ {\HI}}= {\n}_{ {\H}_2}= {\n}_{ {\I}_2}\;\;\text " so "\; {\K}_{ {\P}}=1

1= {\x} × 10^{-1}\; {\x}=10

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