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JEE Main Chemistry Class 11 Solutions Part 2 Questions

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Question : 31 of 80

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What weight of glucose must be dissolved in 100g of water to lower the vapour pressure by 0.20‌mmHg ?
(Assume dilute solution is being formed)
Given : Vapour pressure of pure water is 54.2‌mmHg at room temperature. Molar mass of glucose is 180gmol−1

[11-Apr-2023 shift 2]

2.59g
3.59g
3.69g
4.69g

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