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JEE Main 9 April 2017 Paper Solved Paper

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Question : 73

Total: 90

Let f be a polynomial function such that f(3x)=f′(x)⋅f′′(x), for all x∊R. Then :

[Main 9 April 2017]

f(2)+f′(2)=28
f′′(2)−f′(2)=0
f′′(2)−f(2)=4
f(2)−f′(2)+f′′(2)=10

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