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JEE Main 8 April 2017 Paper Solved Paper
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© examsnet.com
Question : 28
Total: 90
A signal of frequency 20 kHz and peak voltage of 5 Volt is used to modulate a carrier wave of frequency 1.2 MHz and peak voltage 25 Volts. Choose the correct statement.
[Main 8 April 2017]
Modulation index=5, side frequency bands are at 1400 kHz and 1000 kHz
Modulation index=5, side frequency bands are at 21.2 kHz and 18.8 kHz
Modulation index=0.8, side frequency bands are at 1180 kHzand 1220 kHz
Modulation index=0.2, side frequency bands are at 1220 kHzand 1180 kHz
Validate
Solution:
Modulation index
=
m
=
V
m
V
0
=
1
5
=
0.2
Frequency
=
12
×
10
3
kHz
F
=
12.00
kHz
F
1
=
1200
−
20
=
1180
kHz
F
2
=
1200
+
20
=
1220
kHz
© examsnet.com
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