3gm Acetic Acid + 250 ml 0.1 M HCl +Water → made to 500 ml solution. ⇒ 500 ml solution has 25 meq of HCl ∴ 20 ml solution has 50 meq of CH3COOH, 1 meq of HCl, 2 meq of CH3COOH We have added 2.5 meq. of NaOH (5M,
1
2
ml) Finally, NaOH & HCl are completely consumed and we are left with 0.5 meq of CH3COOH and 1.5 meq of CH3COONa pH=pKa+log‌