Given, Angle of inclination, θ = 30º Acceleration, a=10ms−2 Acceleration due to gravity, g=10ms−2 According to the question the car and bob is as shown below,
Here, F'is the pseudo force acting on the bob when we considered it from car’s frame and T is the tension on the string. In equilibrium, ΣFx=0 and ΣFy=0 ⇒F′‌cos‌30°=T‌sin‌α ma‌cos‌30°‌sin‌α=T ...(i) where, m is the mass of the bob. F′‌sin‌30°+mg=T‌cos‌α ⇒ma‌sin‌30°+mg=
ma‌cos‌30°
sin‌α
(cos‌α) [∵ using Eq. (i)] ⇒a‌sin‌30°+g=