JEE Main 26 Feb 2021 Shift 2 Solved Paper

(A) Siderite ( FeCO3 ) is the ore of Fe⇒ (iii) of List-II.
(B) Calamine (ZnCO3) is the ore of Zn⇒ (v) of List - II.
(C) Malachite [CuCO3⋅Cu(OH)2] is the ore of Cu⇒ (i) of List II.
(D) Cryolite (Na3AIF6) is the ore of Al⇒ (iv) of List II. (as well as F2 )
So, option -(c) is the correct matching.
Note Siderite and calamine are carbonate ores whereas malachite is basic carbonate ore. Cryolite is the thioxide ore.