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JEE Main 25 July 2021 Shift 1 Solved Paper
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Section:
Mathematics
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© examsnet.com
Question : 61
Total: 90
A spherical gas balloon of radius 16 meter subtends an angle 60° at the eye of the observer A while the angle of elevation of its center from the eye of A is 75°. Then the height (in meter) of the top most point of the balloon from the level of the observer's eye is :
[25 Jul 2021 Shift 1]
8
(
2
+
2
√
3
+
√
2
)
8
(
√
6
+
√
2
+
2
)
8
(
√
2
+
2
+
√
3
)
8
(
√
6
−
√
2
+
2
)
Validate
Solution:
O → centre of sphere
P,Q → point of contact of tangents from A
Let T be top most point of balloon & R be foot of perpendicular from O to ground.
From triangle
O
A
P
,
O
A
=
16
cosec
30
°
=
32
From triangle
A
B
O
,
O
R
=
O
A
sin
75
°
=
32
(
√
3
+
1
)
2
√
2
So level of top most point
=
O
R
+
O
T
=
8
(
√
6
+
√
2
+
2
)
© examsnet.com
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