In △PAQ,tan30∘=AQPQ⇒31=x+hh⇒x+h=3h⇒x=(3−1)h∵ Speed = Time Distance ∴ Speed from A to B=20AB=20x Also, distance from B to Q=h∴ Time taken to reach Q from B= Speed BQ=x/20h=xh×20[∵x=(3−1)h]=(3−1)hh×20=(3−1)(3+1)(3+1)×20=2(3+1)×20=10(3+1)
