=3x2+6x Slope of line joined by (x1,y1) and (0,0) is =‌
y0−0
x1−0
∴‌
y1
x1
=3x12+6x1 ⇒y1=3x13+6x12......‌ (1) ‌ Point (x1,y1) is on the line, ∴y1=x13+3x12+5....(2) ∴3x13+6x12=x13+3x12+6 ⇒2x13+3x12−5=0 x=1 satisfy the equation ‌ Now, ‌y1=x13+3x12+5 =1+3+5 =9 ∴(x1,y1)=(1,9) Option D does not satisfy point (1,9).