Solution:
R is reflexive ⇒R have (1,1),(2,2),(3,3)
R is transitive
‌∵(1,2),(23)∈R‌‌∴(1,3)∈R
‌∴‌‌R1={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)}
Clearly R1 is reflexive and transitive but not symmetric.
Similarly,
‌R2={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3),(3,2)}
‌R3={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3),(2,1)}
Therefore, 3 relations are possible
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