The position vectors of two 1 kg particles, ( A ) and ( B ) , are given by → r A = ( α 1 t 2 ^ i + α 2 t ^ j + α 3 t ^ k ) m and → r B = ( β 1 t ^ i + β 2 t 2 ^ j + β 3 t ^ k ) m , respectively; ( α 1 = 1 m ∕ s 2 , α 2 = 3 m ∕ s 2 , α 3 = 2 m ∕ s , β 1 = 2 m ∕ s . , β 2 = − 1 m ∕ s 2 , β 3 = 4 p m ∕ s ), where t is time, n and p are constants. At t = 1 s , | → V A | = | → V B | and velocities → V A and → V B of the particles are orthogonal to each other. At t = 1 s , the magnitude of angular momentum of particle ( A ) with respect to the position of particle (B) is √ L kgm 2 s − 1 . The value of L is ______ . [22 Jan 2025 Shift 1]

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JEE Main 22 Jan 2025 Shift 1 Paper

SECTION - B
Numerical Value Type Questions: This section contains 5 Numerical based questions. The answer to each question should be rounded-off to the nearest integer.

Section: Physics

Question : 46

Total: 75

The position vectors of two 1 kg particles, (A) and (B), are given by

)m, respectively; (α1=1m∕ s2,α2=3m∕ s2,α3=2m∕ s,β1=2m∕ s., β2=−1m∕ s2,β3=4pm∕ s ), where t is time, n and p are constants. At t=1 s,|

B of the particles are orthogonal to each other. At t=1 s, the magnitude of angular momentum of particle (A) with respect to the position of particle (B) is √Lkgm2 s−1. The value of L is ______ .

[22 Jan 2025 Shift 1]

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