Let the organic compound is R – Br R−Br+AgNO3––––––––>AgBr↓ So number of moles of AgBr ≡ Number of moles of R – Br ≡ Number of moles of Br
141×10−3
188
= number of moles of Br=0.75×10−3 Mass of bromine =0.75×80×10−3g=60 mg Percentage of bromine =