In presence of SFL Δ0>P means pairing occurs therefore For Fe+2→3d6
∴ No of unpaired e−(s)=0 ∴µ=√n(n+2)BM=0 [n= No of unpaired e−(s)] In NiCl2Ni+2 is having configuration 3d8 ∴ Number of unpaired electron =2 After formation of oxidised product [Ni(CN)6]−2Ni+4 is obtained Ni+4⇒3d6 and CN−is strong field ligand ∴ number of unpaired electrons =0 ∴ The charge is 2−0=2