Given, initial angular speed, ω0=600rpm=10rps Final angular speed, ωF=1800rpm=30rps Time, t=10s ∵ We know that ωF=ω0+αt ⇒‌‌30=10+α×10 ⇒‌‌‌
30−10
10
=α ⇒‌‌α=‌
20
10
=2rps2 Angular displacement is calculated by the rotational equation of motion as θ=ω0t+‌
1
2
αt2 where, θ is the angular displacement. ⇒θ=10×10+‌
1
2
×2×(10)2 ⇒θ=100+100 ⇒θ=200rad Number of rotations =‌