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Test Index
JEE Main 17 March 2021 Shift 1 Solved Paper
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Section:
Chemistry
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Question : 59 of 90
Marks:
+1
,
-0
The oxygen dissolved in water exerts a partial pressure of
20
kPa
20\;\text{kPa}
20
kPa
in the vapour above water. The molar solubility of oxygen in water is .....
×
1
0
−
5
mol
dm
−
3
\times 10^{-5}\;\text{mol}\;\text{dm}^{-3}
×
1
0
−
5
mol
dm
−
3
. (Round off to the nearest integer).
[Given, Henry's law constant
(
K
H
)
(K_{H})
(
K
H
)
=
8.0
×
1
0
4
kPa
=8.0 \times 10^{4}\;\text{kPa}
=
8.0
×
1
0
4
kPa
for
O
2
\mathrm{O}_{2}
O
2
, density of water with dissolved oxygen
=
1.0
kg
dm
−
3
=1.0\;\text{kg}\;\text{dm}^{-3}
=
1.0
kg
dm
−
3
].
[17 Mar 2021 Shift 1]
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