Test Index

Wave Optics

Section: Physics

Question : 10 of 18

Marks: +1, -0

S_1

S_2

\lambda=600

\Delta\theta

The total number of fringes produced between $P_1$ and $P_2$ in the first quadrant is close to 3000
A dark spot will be formed at the point $P_2$
At $P_2$ 2 the order of the fringe will be maximum
The angular separation between two consecutive bright spots decreases as we move from $P_1$ and $P_2$ he angular separation between two consecutive bright spots decreases as we move from

Solution:

P_1,\Delta x=0

P_2,\Delta x=d=3000\lambda

so,between

P_1

and

P_2

2999 bright fringes will be formed.

So, A is correct

P_2

, there will be bright fringe.

So, B is incorrect

P_2

there will be 3000th bright fringe

At angle θ, Δx=dsinθ

(assuming the circle to be of large radius) Rate of change of path difference is

\frac{d}{d\theta}(\Delta x)=d\cos\theta

Which decreases with increasing θ. so for small values of θ, path difference increases sharply with increases in θ resulting in closer fringes.

So, angular separation between consecutive bright sports increases as we move from 1 2 P P to .

So, D is incorrect

Go to Question:

Prev Question

Next Question