Electrostatics

For a uniformly charged spherical shell, the graph due to electric field lines (inside) and the electric potential (inside) are depicted in Figs. (a) and (b), respectively. • Electric field [Fig. (a)]: $E_{\text{inside}}$ = 0, for r < R; $E_{\text{outside}}$ = $\frac{kQ}{r^2}$ , for r ≥ R • Electric potential [Fig. (b)]: $V_{\text{inside}}$ = $\frac{kQ}{R}$, for r ≤ R; $V_{\text{outside}}$ = $\frac{kQ}{r}$ , for r ≥ R where k = $\frac{1}{4\pi\varepsilon_0}$. Hence, the correct graph is the onedepicted in option (D). The dotted line shows the resultant graph of V(r) versus r.