Test Index

Heat and Thermodynamics

Section: Physics

Question : 49 of 69

Marks: +1, -0

The figure below shows the variation of specific heat capacity (C) of a solid as a function of temperature (T). The temperature is increased continuously from 0 to 500 K at a constant rate. Ignoring any volume change, the following statement(s) is (are) correct to a reasonable approximation.

[JEE Adv 2013 P2]

the rate at which heat is absorbed in the range 0 - 100 K varies linearly with temperature T.
heat absorbed in increasing temperature from 0 - 100 K is less than the heat required for increasing the temperature from 400 - 500 K.
there is no change in the rate of absorption in the range 400 - 500 K
the rate of heat absorption increases in the range 200 -200 K

Validate

Solution:

q = mCT

\frac{dq}{dt}

= mc

\frac{dT}{dt}

R = rate of absorption of heat =

\frac{dq}{dt} \propto C

(i) in 0-100 k
C increases, so R increases but not linearly
(ii) Δq = mCΔT as C is more in (400 k - 500 k) then (0- 100 k) so heat is increasing.
(iii) C remains constant so there no change in R from (400 k -500 k)
(iv) C is increased so R is increased in range (200 k -300 k)

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