JEE Advanced Model Paper 2 with solutions for online practice

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Answer Q - 16 , Q - 17 and Q - 18 by appropriately matching the information given in the three columns of the following table.

Electron is given velocity according to column I any one of the electric fields of column II and any one of the electric field of column III is switched on. Neglect the gravitational field.

Column-I : Initial Velocity of electron	Column-II : Intensity of electric field	Column-III : Intensity of electric field
A) $V_1↖{→}$ = $(V_{0i}^{\hat{\phantom{}}})$ at position (0, 0, 0)	I) $E_1↖{-}$ = ${xi\uparrow^{{}}/{{x^2+y^2}}}$	P) $E_1↖{-}$ = 2 $i\uparrow\{\text{\textasciicircum}\}$
B) $V_2↖{→}$ = $(V_0j^{\wedge})$ at position s	II) $E_2↖{-}$ = 2 $j\uparrow{\hat{}}$	$E_2↖{-}$ = ${yj\uparrow^{\wedge}}/{{x^2}+{y^2}}$
$V_3↖{→}$ = $(V_0k^{\uparrow})$ at any position	$E_3↖{-}$ = 2 $k\nwarrow\text{\textasciicircum}$	R) $E_3↖{-}$ = 2 $k\uparrow{\hat{}}$
D) $V_4↖{→}$ = $(V_{0i}^{↖} + V_{0j}^{↖})$ at any position	IV) $E_4↖{-}$ = $2i^{\wedge}+2j^{\wedge}$	$E_4↖{-}$ = $2i\uparrow^{\wedge}-2j\uparrow^{\wedge}$

Question : 16 of 54

Marks: +1, -0

In which case will the particle move in straight line

A,III,P
C,III,R
B,I,S
C,III,P

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